25s^2+60s=36

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Solution for 25s^2+60s=36 equation:



25s^2+60s=36
We move all terms to the left:
25s^2+60s-(36)=0
a = 25; b = 60; c = -36;
Δ = b2-4ac
Δ = 602-4·25·(-36)
Δ = 7200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{7200}=\sqrt{3600*2}=\sqrt{3600}*\sqrt{2}=60\sqrt{2}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60\sqrt{2}}{2*25}=\frac{-60-60\sqrt{2}}{50} $
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60\sqrt{2}}{2*25}=\frac{-60+60\sqrt{2}}{50} $

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